Ahlam's Blog Space
Sunday, 18 March 2018
Thursday, 1 March 2018
Friday, 13 May 2016
SPA 40 Programs Solution
1. Write a program to accept a two digit
number and display it in reversed form.
|
Solution:
#include<stdio.h>
void main()
{
int no, unit, ten,rev=0;
printf("\n Enter the
no:");
scanf("%d",&no);
unit=no%10;
ten=no/10;
rev=unit*10+ten;
if(no%10==0)
printf("The
reverse of the no is 0%d",rev);
else
printf("The
reverse of the no is %d",rev);
}
Output:
Enter the no:50
The reverse of the no is 05
|
2. Write a program to display the first n
natural numbers, where the value of n is taken from user.
|
Solution:
#include<stdio.h>
void main()
{
int n,i,sum=0;
printf("\n Enter the
value of n:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum=sum+i;
}
printf("The sum of n
natural nos is %d",sum);
}
Output:
Enter the value of n:5
The sum of n natural nos is 15
|
3. Write a program to find the factorial of
a number.
|
Solution:
#include<stdio.h>
void main()
{
int n,i,fact=1;
printf("\n Enter the
no whose factorial you want to find:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
fact=fact*i;
}
printf("%d!=%d",n,fact);
}
Output:
Enter the no whose factorial you want to find:5
5!=120
|
4. Write a program to display the
multiplication table of a user entered number. The table must be upto 10.
|
Solution:
#include <stdio.h>
int main()
{
int n, i, j;
printf("Enter an
integer to find multiplication table: ");
scanf("%d",&n);
for(i=1;i<=n;++i)
{
for(j=1;j<=10;j++)
{
printf("%d\t", i*j);
}
printf("\n");
}
return 0;
}
Output:
Enter an integer to find multiplication table: 4
1 2 3
4 5 6
7 8
9 10
2 4 6
8 10 12
14 16 18
20
3 6 9
12 15 18
21 24 27
30
4 8 12
16 20 24
28 32 36
40
|
5.
Write
a program to calculate the value of the following series.
1/2 + 1/3 +1/4…..1/n
|
Solution:
#include <stdio.h>
int main()
{
int n, i;
float sum=0.0;
printf("Enter an
integer No: ");
scanf("%d",&n);
for(i=2;i<=n;++i)
{
sum=sum+(float)1/i;
}
printf("\nThe sum of
series 1/2+1/3+...1/n is %f",sum);
return 0;
}
Output:
Enter an integer No: 5
The sum of series 1/2+1/3+...1/n is 1.283333
|
6. Write a program to display the following
for the user’s specified number of lines.
*
**
***
****
*****
|
n lines
|
Solution:
#include <stdio.h>
int main()
{
int i,j,n;
printf("Enter line no:");
scanf("%d",&n);
for ( i = 1; i <= n; i++)
{
for ( j = 1; j <= i; j++)
{
printf("*");
}
printf("\n");
}
return 0;
}
Output:
Enter line no:6
*
**
***
****
*****
******
|
7. Write a program to display the following
for the user specified number of lines.
*
**
***
****
*****
******
|
n lines
|
Solution:
#include <stdio.h>
int main()
{
int i,j,n;
printf("Enter line no:");
scanf("%d",&n);
for ( i = 1; i <= n; i++)
{
for ( j = n; j >= i; j--)
{
printf(" ");
}
for ( j = 1; j <=i; j++)
{
printf("* ");
}
printf("\n");
}
return 0;
}
Output:
Enter line no:6
*
* *
* * *
* * * *
* * * * *
* * * * * *
|
8. Write
a program to display the following asking the user for the number of
lines
1
1 2
1 2 3
1 2 3 4
|
Solution:
#include <stdio.h>
int main()
{
int i,j,n;
printf("Enter line no:");
scanf("%d",&n);
for ( i = 1; i <= n; i++)
{
for ( j = 1; j <= i; j++)
{
printf("%d",j);
}
printf("\n");
}
return 0;
}
Output:
Enter line no:5
1
12
123
1234
12345
|
9. Write a program to display the following
asking the user for the number of lines.
1
1 2 A
1 2 3 A B
1 2 3 4 A B C
|
Solution:
#include <stdio.h>
int main()
{
int i,j,k,l,n,
alpha=65;
printf("Enter
line no:");
scanf("%d",&n);
for(i=1;i<=n;i++) //Row
{
for(j=n;j>i;j--)
{
printf(" ");
}
for(k=1;k<=i;k++) // inner loop for no
triangle
{
printf("%d",k);
}
for(alpha=65,l=1;l<i;l++,alpha++) //
inner loop for alphabet triangle
{
printf("%c",(char)alpha);
}
printf("\n");
}
return 0;
}
Output:
Enter line no:5
1
12A
123AB
1234ABC
12345ABCD
|
10. Write a program to check if the entered
number is prime number or not.
|
Solution:
#include<stdio.h>
int main()
{
int n,i;
printf("Enter the
No:");
scanf("%d",&n);
for(i=2;i<n;i++)
{
if(n%i==0)
break;
}
if(i==n)
{
printf("%d is a
Prime no\n",n);
}
else
{
printf("%d is not
a Prime no\n",n);
}
return 0;
}
Output:
Enter the No:11
11 is a Prime no
|
11. Write a program to check if the entered
number is Armstrong or not.
|
Solution:
/* C program to check whether a number entered by user is Armstrong
or not. */
#include <stdio.h>
#include<math.h>
int main()
{
int n, n1, rem, len=0, arm=0;
printf("Enter a
positive integer: ");
scanf("%d",
&n);
n1=n;
while(n1!=0)
{
len++;
n1/=10;
}
n1=n;
while(n1!=0)
{
rem=n1%10;
arm=arm+pow(rem,len);
n1/=10;
}
if(arm==n)
printf("%d is an
Armstrong number.",n);
else
printf("%d is not an
Armstrong number.",n);
}
Output:
Enter a positive integer: 153
153 is an Armstrong number.
|
12. Write a program to check if the year
entered is leap year or not.
|
Solution:
#include<stdio.h>
int main()
{
int year;
printf("Enter any
year: ");
scanf("%d",&year);
if(((year%4==0)&&(year%100!=0))||(year%400==0))
printf("%d is a
leap year",year);
else
printf("%d is not
a leap year",year);
return 0;
}
Output:
Enter any year: 2016
2016 is a leap year
|
13. Write a program to display the user
entered number in words.
|
Solution:
#include<stdio.h>
int main()
{
int no,no1,rem,rev=0;
printf("Enter the
No:-> ");
scanf("%d",&no);
no1=no;
while (no1!=0)
{
rem = no1%10;
rev=rev*10+rem;
no1=no1/10;
}
no1=rev;
while(no1!=0)
{
rem=no1%10;
switch(rem)
{
case 1:
printf("One
");
break;
case 2:
printf("Two
");
break;
case 3:
printf("Three
");
break;
case 4:
printf("Four
");
break;
case 5:
printf("Five
");
break;
case 6:
printf("Six
");
break;
case 7:
printf("Seven
");
break;
case 8:
printf("Eight
");
break;
case 9:
printf("Nine
");
break;
case 0:
printf("Zero
");
break;
default:
printf("invalid number\nPlease try again ....\n");
break;
}
no1=no1/10;
}
return 0;
}
Output:
Enter the No:-> 405
Four Zero Five
|
14. Write a program to find value of y using
function, where y=xn.
|
Solution:
#include<stdio.h>
void power(void);
int main()
{
power();
return 0;
}
void power()
{
int x,n,i,res=1;
printf("\n Enter the
base and index:");
scanf("%d%d",&x,&n);
for(i=1;i<=n;i++)
{
res=res*x;
}
printf("%d^%d=%d",x,n,res);
}
Output:
Enter the base and index:2
5
2^5=32
|
15. Write a menu driven program to perform
add / subtract / multiply / divide / modulus based on the users choice.
|
Solution:
#include<stdio.h>
int main()
{
int choice,a,b,res;
printf("Enter the
value of A and B\n");
scanf("%d%d",&a,&b);
printf("Enter your
choice\n");
printf("Press 1 to
Add\n");
printf("Press 2 to
Subtract\n");
printf("Press 3 to
Multiply\n");
printf("Press 4 to
Divide\n");
scanf("%d",&choice);
switch(choice)
{
case 1: res=a+b;
printf("%d+%d=%d",a,b,res);
break;
case 2: res=a-b;
printf("%d-%d=%d",a,b,res);
break;
case 3: res=a*b;
printf("%d*%d=%d",a,b,res);
break;
case 4:
printf("Quotient of %d/%d=%f",a,b,(float)a/b);
printf("\nRemainder of
%d/%d=%d",a,b,a%b);
break;
default:printf("Invalid Input");
}
}
Output:
Enter the value of A and B
3
5
Enter your choice
Press 1 to Add
Press 2 to Subtract
Press 3 to Multiply
Press 4 to Divide
4
Quotient of 3/5=0.600000
Remainder of 3/5=3
|
16. Write a program to display the month name
by accepting the month number from user.
|
Solution:
#include<stdio.h>
int main()
{
int n;
printf("Month No:->
");
scanf("%d",&n);
switch(n)
{
case 1:
printf("January\n");
break;
case 2:
printf("February\n");
break;
case 3:
printf("March\n");
break;
case 4:
printf("April\n");
break;
case 5:
printf("MAy\n");
break;
case 6:
printf("June\n");
break;
case 7:
printf("July\n");
break;
case 8:
printf("August\n");
break;
case 9:
printf("September\n");
break;
case 10:
printf("October\n");
break;
case 11:
printf("November\n");
break;
case 12:
printf("December\n");
break;
default:
printf("invalid Month
number\nPlease try again ....\n");
break;
}
return 0;
}
Output:
Month No:-> 6
June
|
17. Write a program to find GCD and LCM of
two numbers.
|
Solution:
#include<stdido.h>
void main() { int i,a,b,min,max,lcm,hcf; clrscr(); printf("Enter the two numbers:"); scanf("%d%d",&a,&b); //find out smallest and largest and assign them to min and max variable respectively a<b?(min=a,max=b):(min=b,max=a); printf("%d%d",min,max); for(i=min;i>=1;i--) { if(max%i==0&&min%i==0) { hcf=i; break; } } lcm=(a*b)/hcf; printf("\nThe LCM=%d\nThe GCD=%d",lcm,hcf); getch(); } Output:
Enter the two numbers:90
75 7590 The LCM=450 The GCD=15 |
18. Write a program to add two numbers using
function.
|
Solution:
#include<stdio.h>
void add(void);
int main()
{
add();
return 0;
}
void add()
{
int a,b,sum;
printf("\n Enter the
nos to be added:");
scanf("%d%d",&a,&b);
sum=a+b;
printf("%d+%d=%d",a,b,sum);
}
Output:
Enter the nos to be added:
12
87
12+87=99
|
19. Write a program to find the factorial of
a number using a function.
|
Solution:
#include<stdio.h>
void factorial(void);
int main()
{
factorial();
return 0;
}
void factorial()
{
int n,i,fact=1;
printf("\n Enter the
no whose factorial you want to find:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
fact=fact*i;
}
printf("%d!=%d",n,fact);
}
Output:
Enter the no whose factorial you want to find:5
5!=120
|
20. Write a program to find factorial of a
given number, using a recursive function.
|
Solution:
#include<stdio.h>
int factorial(int);
int main()
{
int n,i,fact;
printf("\n Enter the
no whose factorial you want to find:");
scanf("%d",&n);
fact= factorial(n);
printf("%d!=%d",n,fact);
return 0;
}
int factorial(int n)
{
if(n==0)
{
return(1);
}
else
{
return(n*factorial(n-1));
}
}
Output:
Enter the no whose factorial you want to find:5
5!=120
|
21. Write a program to find value of y using
recursive function, where y=xn.
|
Solution:
#include<stdio.h>
int power(int,int);
int main()
{
int x,n,i,res=1;
printf("\n Enter the
base and index:");
scanf("%d%d",&x,&n);
res= power(x,n);
printf("%d^%d=%d",x,n,res);
return 0;
}
int power(int x,int n)
{
if(n==0)
{
return(1);
}
else
{
return(x*power(x,n-1));
}
}
Output:
Enter the base and index:2
5
2^5=32
|
22. Write a program to accept ‘n’ integers
from user into an array and display the average of these numbers.
|
Solution:
# include<stdio.h>
void main()
{
int arr[20];
int i,n;
float sum=0,avg=0;
printf("How many
elements you want in array: ");
scanf("%d",&n);
printf("Enter %d
elements\n",n);
for(i=0;i<n;i++)
{
scanf("%d",&arr[i]);
sum = sum + arr[i];
}
printf("\n Sum of
array elements = %f",sum);
avg = sum/10;
printf("\n Average =
%f",avg);
}
Output:
How many elements you want in array: 5
Enter 5 elements
1
1
1
1
1
Sum of array elements =
5.000000
Average = 0.500000
|
23. Write a program to find an element in an
array and display the index of the element.
|
Solution:
#include<stdio.h>
void main()
{
int
a[10]={1,0,3,6,8,9,5,8,0,2},d,i,c=0;
d=10;
printf("\nEnter
the Element to be searched in the Array:");
scanf("%d",&d);
for(i=0;i<10;i++)
{
if(d==a[i])
{
c++;
printf("\n%d found at %d Location",d,i);
}
}
if(c==0)
{
printf("\n%d
not found");
}
else
{
printf("\n%d
found %d times",d,c);
}
}
Output:
Enter the Element to be searched in the Array:8
8 found at 4 Location
8 found at 7 Location
8 found 2 times
|
24. Write a program to sort numbers in
ascending order.
|
Solution:
#include<stdio.h>
void main()
{
int ar[100],j,n,i,tmp;
printf(" Enter the
size of the array \t");
scanf("%d",&n);
printf("Now enter the
elements in the array \t");
for(i=0;i<n;i++)
{
scanf("%d",&ar[i]);
}
printf("\n Array is :
");
for(i=0;i<n;i++)
{
printf("\t
%d",ar[i]);
}
for(i=0;i<=n-2;i++)
{
for(j=i+1;j<=n-1;j++)
{
if(ar[i]>ar[j])
{
tmp=ar[j];
ar[j]=ar[i];
ar[i]=tmp;
}
}
}
printf("\n\n Array in
the Ascending order is - \n");
for(i=0;i<n;i++)
{
printf("\t
%d",ar[i]);
}
}
Output:
Enter the size of the array
5
Now enter the elements in the array 8
9 2 -1 4
Array is : 8
9 2 -1
4
Array in the Ascending order
is -
-1 2
4 8 9
|
25. Write a program to accept ‘n’ integers from
user into an array and display the largest element.
|
Solution:
#include<stdio.h>
void main()
{
int ar[100],l,n,i;
printf(" Enter the
size of the array \t");
scanf("%d",&n);
printf("Now enter the
elements in the array \t");
for(i=0;i<n;i++)
{
scanf("%d",&ar[i]);
}
printf("\n Array is :
");
for(i=0;i<n;i++)
{
printf("\t
%d",ar[i]);
}
for(l=ar[0],i=1;i<n;i++)
{
if(l<ar[i])
{
l=ar[i];
}
}
printf("\nLargest
Element in Array is %d",l);
}
Output:
Enter the size of the array
5
Now enter the elements in the array 8 9 6 10 2
Array is : 8
9 6 10
2
Largest Element in Array is 10
|
26. Write a program to accept ‘n’ integers
from user into an array and display the smallest element.
|
Solution:
#include<stdio.h>
void main()
{
int ar[100],s,n,i;
printf(" Enter the size
of the array \t");
scanf("%d",&n);
printf("Now enter the
elements in the array \t");
for(i=0;i<n;i++)
{
scanf("%d",&ar[i]);
}
printf("\n Array is :
");
for(i=0;i<n;i++)
{
printf("\t
%d",ar[i]);
}
for(s=ar[0],i=1;i<n;i++)
{
if(s>ar[i])
{
s=ar[i];
}
}
printf("\nLargest
Element in Array is %d",s);
}
Output:
Enter the size of the array
5
Now enter the elements in the array 8 9 2 6 10
Array is : 8
9 2 6
10
Largest Element in Array is 2
|
27. Write a program to sort numbers in
descending order.
|
Solution:
#include<stdio.h>
void main()
{
int ar[100],j,n,i,tmp;
printf(" Enter the
size of the array \t");
scanf("%d",&n);
printf("Now enter the
elements in the array \t");
for(i=0;i<n;i++)
{
scanf("%d",&ar[i]);
}
printf("\n Array is :
");
for(i=0;i<n;i++)
{
printf("\t
%d",ar[i]);
}
for(i=0;i<=n-2;i++)
{
for(j=i+1;j<=n-1;j++)
{
if(ar[i]<ar[j])
{
tmp=ar[j];
ar[j]=ar[i];
ar[i]=tmp;
}
}
}
printf("\n\n Array in
the Descending order is - \n");
for(i=0;i<n;i++)
{
printf("\t
%d",ar[i]);
}
}
Output:
Enter the size of the array
5
Now enter the elements in the array 2 9 -1 3 8
Array is : 2
9 -1 3
8
Array in the Descending order
is -
9 8
3 2 -1
|
28. Write a program to add two matrices of
size m x n.
|
Solution:
#include <stdio.h>
int main()
{
int m, n, c, d,
first[10][10], second[10][10], sum[10][10];
printf("Enter the
number of rows and columns of matrix\n");
scanf("%d%d",
&m, &n);
printf("Enter the
elements of first matrix\n");
for (c = 0; c < m; c++)
{ for (d = 0; d < n; d++)
{
scanf("%d", &first[c][d]);
}
}
printf("Enter the
elements of second matrix\n");
for (c = 0; c < m; c++)
{ for (d = 0 ; d < n; d++)
{
scanf("%d", &second[c][d]);
}
}
printf("Sum of entered
matrices:-\n");
for (c = 0; c < m; c++)
{
for (d = 0 ; d < n;
d++)
{
sum[c][d] =
first[c][d] + second[c][d];
printf("%d\t", sum[c][d]);
}
printf("\n");
}
return 0;
}
Output:
Enter the number of rows and columns of matrix
2 3
Enter the elements of first matrix
1 1 1 1 1 1
Enter the elements of second matrix
2 2 2 2 2 2
Sum of entered matrices:-
3 3 3
3 3 3
|
29. Write a program to accept two strings,
join them and display the result using string header file.
|
Solution:
#include<stdio.h>
#include<string.h>
int main()
{
char str1[20],str2[20];
puts("Enter first
string");
gets(str1);
puts("Enter second
string");
gets(str2);
printf("Before
concatenation the strings are\n");
puts(str1);
puts(str2);
strcat(str1,str2);
printf("After
concatenation the strings are\n");
puts(str1);
puts(str2);
return 0;
}
Output:
Enter first string
Ahlam
Enter second string
Ansari
Before concatenation the strings are
Ahlam
Ansari
After concatenation the strings are
AhlamAnsari
Ansari
|
30. Write a program to accept a string and
find its length without using the string header file.
|
Solution:
#include <stdio.h>
int main(void)
{
char a[10];
int len;
puts("Enter the
string");
gets(a);
for(len=0;a[len]!='\0';len++);
printf("Length of
string :%s is %d",a,len);
Output:
Enter the string
Ahlam
Length of string :Ahlam is 5
|
31. Write a program to reverse a user entered
string.
|
Solution:
#include<stdio.h>
int main()
{
int i=0,j=0;
char str[20],rev[20];
puts("Enter the
string");
gets(str);
printf("Before reversing
the string value is: %s",str);
while(str[i]!='\0')
{
i++;
}
i=i-1;
while(str[j]!='\0')
{
rev[j]=str[i];
j++;
i--;
}
rev[j]='\0';
printf("After reversing
the string is %s",rev);
return 0;
}
Output:
Enter the string
ansari
Before reversing the string value is: ansariAfter reversing the
string is irasna
|
32. Write a program to check whether the
entered string is palindrome or not (Do not use the string header file).
|
Solution:
#include <stdio.h>
int main(void)
{
char a[10];
int i,len;
puts("Enter the
string");
gets(a);
for(len=0;a[len]!='\0';len++);
for(i=0;i<len/2;i++)
{
if(a[i]!=a[len-1-i])
{
break;
}
}
if(i==len/2)
{
printf("%s is
palindrome",a);
}
else
{
printf("%s is not
palindrome",a);
}
return 0;
}
Output:
Enter the string
nitin
nitin is palindrome
|
33. Write a program to swap two numbers using
a function. Pass the values to be swapped to this function using
call-by-value method.
|
Solution:
#include<stdio.h>
void swap(int,int);
void main()
{
int a,b;
printf("Enter
the value of A");
scanf("%d",&a);
printf("Enter
the value of B");
scanf("%d",&b);
printf("\nBefore
Swapping : A=%d and B=%d",a,b);
swap(a,b);
}
void swap(int a, int b)
{
int t;
t=a;
a=b;
b=t;
printf("\nAfter
Swapping : A=%d and B=%d",a,b);
}
Output:
Enter the value of A4
Enter the value of B6
Before Swapping : A=4 and B=6
After Swapping : A=6 and B=4
|
34. Write a program to swap two numbers using
a function. Pass the values to be swapped to this function using call-by-reference
method.
|
Solution:
#include<stdio.h>
void swap(int *,int *);
void main()
{
int a,b;
printf("Enter
the value of A");
scanf("%d",&a);
printf("Enter
the value of B");
scanf("%d",&b);
printf("\nBefore
Swapping : A=%d and B=%d",a,b);
swap(&a,&b);
}
void swap(int *aptr, int *bptr)
{
int t;
t=*aptr;
*aptr=*bptr;
*bptr=t;
printf("\nAfter
Swapping : A=%d and B=%d",*aptr,*bptr);
}
Output:
Enter the value of A 10
Enter the value of B 12
Before Swapping : A=10 and B=12
After Swapping : A=12 and B=10
|
35. Write a program to accept basic salary from the keyboard. Calculate the gross
salary that includes basic salary, 60% DA and 45% HRA and exclude 10% income tax.
|
Solution:
#include<stdio.h>
#include<conio.h>
void main()
{
float
basic,gross,hra,da,it,net;
clrscr();
printf("Enter
the Basic Salary");
scanf("%f",&basic);
da =
basic*(float)60/100;
hra =
basic*(float)45/100;
gross =
basic+hra+da;
it =
gross*(float)10/100;
net = gross-it;
printf("\nBasic
Salary: $%f/-",basic);
printf("\nDA:
$%f/-",da);
printf("\nHRA:
$%f/-",hra);
printf("\nGross
Salary: $%f/-",gross);
printf("\nNet
Salary: $%f/-",net);
getch();
}
Output:
Enter the Basic Salary
2000
Basic Salary: $2000.000000/-
DA: $1200.000000/-
HRA: $800.000000/-
Gross Salary: $4000.000000/-
Net Salary: $3600.000000/-
|
36. Write a program to accept three integer numbers from user and display the smallest
of three using the conditional operator.
|
Solution:
#include<stdio.h>
void main()
{
int a,b,c;
printf("Enter
three integer numbers");
scanf("%d%d%d",&a,&b,&c);
(a<b&&a<c)?printf("%d
is the Smallest",a):((b<a&&b<c)?printf("%d is the
Smallest",b):printf("%d is the Smallest",c));
}
Output:
Enter three integer numbers1 4 -2
-2 is the Smallest
|
37. Write a program to swap two integers without using temporary variable.
|
Solution:
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("Enter
the value of A");
scanf("%d",&a);
printf("Enter
the value of B");
scanf("%d",&b);
printf("\nBefore
Swapping : A=%d and B=%d",a,b);
a=a+b;
b=a-b;
a=a-b;
printf("\nAfter
Swapping : A=%d and B=%d",a,b);
getch();
}
Output:
Enter the value of A
234
Enter the value of B
123
Before Swapping : A=234 and B=123
After Swapping : A=123 and B=234
|
38. Write a program to
generate n fibbonacci elements.
|
Solution:
#include<stdio.h>
int main()
{
int n,i, a=0,b=1,c;
printf("Enter no. of elements you want to display in
series");
scanf("%d",&n);
printf("%d\t%d\t",a,b);
for(i=1;i<=n-2;i++)
{
c=a+b;
a=b;
b=c;
printf("%d\t",c);
}
return 0;
}
Output:
Enter no. of elements you want to display in series6
0 1 1
2 3 5
|
39. Write a program to accept three integer numbers from user and display the
largest of three using if-else.
|
Solution:
#include<stdio.h>
void main()
{
int a,b,c;
printf("Enter three
integer numbers");
scanf("%d%d%d",&a,&b,&c);
if(a>b&&a>c)
printf("%d is the
largest",a);
else
if(b>a&&b>c)
printf("%d is the
largest",b);
else
printf("%d is the
largest",c);
}
Output:
Enter three integer numbers 8 6 98
98 is the largest
|
40. Write a program to accept n digit number and display it in reversed form.
|
Solution:
#include<stdio.h>
int main()
{
int no,no1,rem=0, rno=0;
printf("Enter the no
to be reversed");
scanf("%d",&no);
no1=no;
while (no!=0)
{
rem = no%10;
rno=rno*10+rem;
no=no/10;
}
if(no1%10==0)
{
printf("Reverse of
%d is 0%d", no1, rno);
}
else
{
printf("Reverse of
%d is %d", no1, rno);
}
return(0);
}
Output:
Enter the no to be reversed7090
Reverse of 7090 is 0907
|
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